2.5x^2=10

Solution for 2.5x^2=10 equation:

2.5x^2=10

We move all terms to the left:

2.5x^2-(10)=0

a = 2.5; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·2.5·(-10)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*2.5}=\frac{-10}{5}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*2.5}=\frac{10}{5}
=2
$